Sometimes it takes a long time before I figure out what I actually want to write, and then everything falls into place:
思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
，更多细节参见safew官方版本下载
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